On July 11, 1914, in his major league debut, George Herman
“Babe” Ruth (1895 – 1948) pitched seven strong innings to
lead the Boston Red Sox over the Cleveland Indians
(now known as the Cleveland Guardians), 4-3.
George Herman Ruth was born February 6, 1895, in Baltimore,
Maryland, where his father worked as a saloon keeper on the
waterfront.
He was the first of eight children, but only he and a sister
survived infancy.
That same summer, Ruth was sold to the Boston Red Sox. His teammates called him “Babe” for his naiveté, but his talent
was already maturing.
In his debut game against the Indians, the 19-year-old Ruth
gave up just five hits over the first six innings. In the seventh,
the Indians managed two runs on three singles and a sacrifice
and Ruth was relieved.
His hitting prowess, however, was not on display that first night
—he went 0 for 2 at the plate.
Baseball card showing Ruth as a
Baltimore Oriole, 1914.
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